p=sqrt{a/pix} eching

$$p = \sqrt { \frac { a } { \pi x } }$$

a uchun yechish

$$a=\pi xp^{2}$$

$$p\geq 0\text{ and }x\neq 0$$

Ildizli tenglamalarni yechish qadamlari

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\sqrt{\frac{a}{\pi x}}=p$$

Tenglamaning ikkala taraf kvadratini chiqarish.

$$\frac{1}{\pi x}a=p^{2}$$

Ikki tarafini \pi ^{-1}x^{-1} ga bo‘ling.

$$\frac{\frac{1}{\pi x}a\pi x}{1}=\frac{p^{2}\pi x}{1}$$

\pi ^{-1}x^{-1} ga bo'lish \pi ^{-1}x^{-1} ga ko'paytirishni bekor qiladi.

$$a=\frac{p^{2}\pi x}{1}$$

p^{2} ni \pi ^{-1}x^{-1} ga bo'lish.

$$a=\pi xp^{2}$$

a uchun yechish (complex solution)

$$a=\pi xp^{2}$$

$$x\neq 0\text{ and }\left(p=0\text{ or }arg(p)<\pi \right)$$

p uchun yechish (complex solution)

$$p=\sqrt{\frac{a}{\pi x}}$$

$$x\neq 0$$

p uchun yechish

$$p=\sqrt{\frac{a}{\pi x}}$$

$$\left(a\geq 0\text{ and }x>0\right)\text{ or }\left(a\leq 0\text{ and }x<0\right)$$