n^2-25n-144 eching

$$n ^ { 2 } - 25 n - 144$$

Omil

$$\left(n-\frac{25-\sqrt{1201}}{2}\right)\left(n-\frac{\sqrt{1201}+25}{2}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$n^{2}-25n-144=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$n=\frac{-\left(-25\right)±\sqrt{\left(-25\right)^{2}-4\left(-144\right)}}{2}$$

-25 kvadratini chiqarish.

$$n=\frac{-\left(-25\right)±\sqrt{625-4\left(-144\right)}}{2}$$

-4 ni -144 marotabaga ko'paytirish.

$$n=\frac{-\left(-25\right)±\sqrt{625+576}}{2}$$

625 ni 576 ga qo'shish.

$$n=\frac{-\left(-25\right)±\sqrt{1201}}{2}$$

-25 ning teskarisi 25 ga teng.

$$n=\frac{25±\sqrt{1201}}{2}$$

n=\frac{25±\sqrt{1201}}{2} tenglamasini yeching, bunda ± musbat. 25 ni \sqrt{1201} ga qo'shish.

$$n=\frac{\sqrt{1201}+25}{2}$$

n=\frac{25±\sqrt{1201}}{2} tenglamasini yeching, bunda ± manfiy. 25 dan \sqrt{1201} ni ayirish.

$$n=\frac{25-\sqrt{1201}}{2}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{25+\sqrt{1201}}{2} ga va x_{2} uchun \frac{25-\sqrt{1201}}{2} ga bo‘ling.

$$n^{2}-25n-144=\left(n-\frac{\sqrt{1201}+25}{2}\right)\left(n-\frac{25-\sqrt{1201}}{2}\right)$$

Baholash

$$n^{2}-25n-144$$