n^2+3n+3n+6 eching

$$n ^ { 2 } + 3 n + 3 n + 6$$

Omil

$$\left(n-\left(-\sqrt{3}-3\right)\right)\left(n-\left(\sqrt{3}-3\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

6n ni olish uchun 3n va 3n ni birlashtirish.

$$factor(n^{2}+6n+6)$$

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$n^{2}+6n+6=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$n=\frac{-6±\sqrt{6^{2}-4\times 6}}{2}$$

6 kvadratini chiqarish.

$$n=\frac{-6±\sqrt{36-4\times 6}}{2}$$

-4 ni 6 marotabaga ko'paytirish.

$$n=\frac{-6±\sqrt{36-24}}{2}$$

36 ni -24 ga qo'shish.

$$n=\frac{-6±\sqrt{12}}{2}$$

12 ning kvadrat ildizini chiqarish.

$$n=\frac{-6±2\sqrt{3}}{2}$$

n=\frac{-6±2\sqrt{3}}{2} tenglamasini yeching, bunda ± musbat. -6 ni 2\sqrt{3} ga qo'shish.

$$n=\frac{2\sqrt{3}-6}{2}$$

-6+2\sqrt{3} ni 2 ga bo'lish.

$$n=\sqrt{3}-3$$

n=\frac{-6±2\sqrt{3}}{2} tenglamasini yeching, bunda ± manfiy. -6 dan 2\sqrt{3} ni ayirish.

$$n=\frac{-2\sqrt{3}-6}{2}$$

-6-2\sqrt{3} ni 2 ga bo'lish.

$$n=-\sqrt{3}-3$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -3+\sqrt{3} ga va x_{2} uchun -3-\sqrt{3} ga bo‘ling.

$$n^{2}+6n+6=\left(n-\left(\sqrt{3}-3\right)\right)\left(n-\left(-\sqrt{3}-3\right)\right)$$

Baholash

$$n^{2}+6n+6$$

Yechim qadamlari

6n ni olish uchun 3n va 3n ni birlashtirish.

$$n^{2}+6n+6$$