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2\pi \sqrt{\frac{k}{x}}=n
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
\frac{2\pi \sqrt{\frac{1}{x}k}}{2\pi }=\frac{n}{2\pi }
Ikki tarafini 2\pi ga bo‘ling.
\sqrt{\frac{1}{x}k}=\frac{n}{2\pi }
2\pi ga bo'lish 2\pi ga ko'paytirishni bekor qiladi.
\frac{1}{x}k=\frac{n^{2}}{4\pi ^{2}}
Tenglamaning ikkala taraf kvadratini chiqarish.
\frac{\frac{1}{x}kx}{1}=\frac{n^{2}}{4\pi ^{2}\times \frac{1}{x}}
Ikki tarafini x^{-1} ga bo‘ling.
k=\frac{n^{2}}{4\pi ^{2}\times \frac{1}{x}}
x^{-1} ga bo'lish x^{-1} ga ko'paytirishni bekor qiladi.
k=\frac{xn^{2}}{4\pi ^{2}}
\frac{n^{2}}{4\pi ^{2}} ni x^{-1} ga bo'lish.