m(y-2)^2=E eching

$$m ( y - 2 ) ^ { 2 } = E$$

m uchun yechish (complex solution)

$$\left\{\begin{matrix}m=\frac{E}{\left(y-2\right)^{2}}\text{, }&y\neq 2\\m\in \mathrm{C}\text{, }&E=0\text{ and }y=2\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(y-2\right)^{2} kengaytirilishi uchun ishlating.

$$m\left(y^{2}-4y+4\right)=E$$

m ga y^{2}-4y+4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$my^{2}-4my+4m=E$$

m'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(y^{2}-4y+4\right)m=E$$

Ikki tarafini y^{2}-4y+4 ga bo‘ling.

$$\frac{\left(y^{2}-4y+4\right)m}{y^{2}-4y+4}=\frac{E}{y^{2}-4y+4}$$

y^{2}-4y+4 ga bo'lish y^{2}-4y+4 ga ko'paytirishni bekor qiladi.

$$m=\frac{E}{y^{2}-4y+4}$$

E ni y^{2}-4y+4 ga bo'lish.

$$m=\frac{E}{\left(y-2\right)^{2}}$$

m uchun yechish

$$\left\{\begin{matrix}m=\frac{E}{\left(y-2\right)^{2}}\text{, }&y\neq 2\\m\in \mathrm{R}\text{, }&E=0\text{ and }y=2\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(y-2\right)^{2} kengaytirilishi uchun ishlating.

$$m\left(y^{2}-4y+4\right)=E$$

m ga y^{2}-4y+4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$my^{2}-4my+4m=E$$

m'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(y^{2}-4y+4\right)m=E$$

Ikki tarafini y^{2}-4y+4 ga bo‘ling.

$$\frac{\left(y^{2}-4y+4\right)m}{y^{2}-4y+4}=\frac{E}{y^{2}-4y+4}$$

y^{2}-4y+4 ga bo'lish y^{2}-4y+4 ga ko'paytirishni bekor qiladi.

$$m=\frac{E}{y^{2}-4y+4}$$

E ni y^{2}-4y+4 ga bo'lish.

$$m=\frac{E}{\left(y-2\right)^{2}}$$

E uchun yechish

$$E=m\left(y-2\right)^{2}$$