m^2-12m+10 eching

$$m ^ { 2 } - 12 m + 10$$

Omil

$$\left(m-\left(6-\sqrt{26}\right)\right)\left(m-\left(\sqrt{26}+6\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$m^{2}-12m+10=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$m=\frac{-\left(-12\right)±\sqrt{\left(-12\right)^{2}-4\times 10}}{2}$$

-12 kvadratini chiqarish.

$$m=\frac{-\left(-12\right)±\sqrt{144-4\times 10}}{2}$$

-4 ni 10 marotabaga ko'paytirish.

$$m=\frac{-\left(-12\right)±\sqrt{144-40}}{2}$$

144 ni -40 ga qo'shish.

$$m=\frac{-\left(-12\right)±\sqrt{104}}{2}$$

104 ning kvadrat ildizini chiqarish.

$$m=\frac{-\left(-12\right)±2\sqrt{26}}{2}$$

-12 ning teskarisi 12 ga teng.

$$m=\frac{12±2\sqrt{26}}{2}$$

m=\frac{12±2\sqrt{26}}{2} tenglamasini yeching, bunda ± musbat. 12 ni 2\sqrt{26} ga qo'shish.

$$m=\frac{2\sqrt{26}+12}{2}$$

12+2\sqrt{26} ni 2 ga bo'lish.

$$m=\sqrt{26}+6$$

m=\frac{12±2\sqrt{26}}{2} tenglamasini yeching, bunda ± manfiy. 12 dan 2\sqrt{26} ni ayirish.

$$m=\frac{12-2\sqrt{26}}{2}$$

12-2\sqrt{26} ni 2 ga bo'lish.

$$m=6-\sqrt{26}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 6+\sqrt{26} ga va x_{2} uchun 6-\sqrt{26} ga bo‘ling.

$$m^{2}-12m+10=\left(m-\left(\sqrt{26}+6\right)\right)\left(m-\left(6-\sqrt{26}\right)\right)$$

Baholash

$$m^{2}-12m+10$$