m^2+2m=7 eching

$$m ^ { 2 } + 2 m = 7$$

m uchun yechish

$$m=2\sqrt{2}-1\approx 1,828427125$$

$$m=-2\sqrt{2}-1\approx -3,828427125$$

Kvadrat tenglamalaridan foydalanish qoidalari

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$m^{2}+2m=7$$

Tenglamaning ikkala tarafidan 7 ni ayirish.

$$m^{2}+2m-7=7-7$$

O‘zidan 7 ayirilsa 0 qoladi.

$$m^{2}+2m-7=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 2 ni b va -7 ni c bilan almashtiring.

$$m=\frac{-2±\sqrt{2^{2}-4\left(-7\right)}}{2}$$

2 kvadratini chiqarish.

$$m=\frac{-2±\sqrt{4-4\left(-7\right)}}{2}$$

-4 ni -7 marotabaga ko'paytirish.

$$m=\frac{-2±\sqrt{4+28}}{2}$$

4 ni 28 ga qo'shish.

$$m=\frac{-2±\sqrt{32}}{2}$$

32 ning kvadrat ildizini chiqarish.

$$m=\frac{-2±4\sqrt{2}}{2}$$

m=\frac{-2±4\sqrt{2}}{2} tenglamasini yeching, bunda ± musbat. -2 ni 4\sqrt{2} ga qo'shish.

$$m=\frac{4\sqrt{2}-2}{2}$$

4\sqrt{2}-2 ni 2 ga bo'lish.

$$m=2\sqrt{2}-1$$

m=\frac{-2±4\sqrt{2}}{2} tenglamasini yeching, bunda ± manfiy. -2 dan 4\sqrt{2} ni ayirish.

$$m=\frac{-4\sqrt{2}-2}{2}$$

-2-4\sqrt{2} ni 2 ga bo'lish.

$$m=-2\sqrt{2}-1$$

Tenglama yechildi.

$$m=2\sqrt{2}-1 m=-2\sqrt{2}-1$$

Kvadratni yakunlash bo'yicha qadamlar

Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.

$$m^{2}+2m=7$$

2 ni bo‘lish, x shartining koeffitsienti, 2 ga 1 olish uchun. Keyin, 1 ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.

$$m^{2}+2m+1^{2}=7+1^{2}$$

1 kvadratini chiqarish.

$$m^{2}+2m+1=7+1$$

7 ni 1 ga qo'shish.

$$m^{2}+2m+1=8$$

m^{2}+2m+1 omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.

$$\left(m+1\right)^{2}=8$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$\sqrt{\left(m+1\right)^{2}}=\sqrt{8}$$

Qisqartirish.

$$m+1=2\sqrt{2} m+1=-2\sqrt{2}$$

Tenglamaning ikkala tarafidan 1 ni ayirish.

$$m=2\sqrt{2}-1 m=-2\sqrt{2}-1$$