m=2psiDelta(6.7) eching

$$m = 2 \psi \Delta ( 6.7 )$$

Δ uchun yechish

$$\left\{\begin{matrix}\Delta =\frac{5m}{67\psi }\text{, }&\psi \neq 0\\\Delta \in \mathrm{R}\text{, }&m=0\text{ and }\psi =0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

13,4 hosil qilish uchun 2 va 6,7 ni ko'paytirish.

$$m=13,4\psi \Delta$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$13,4\psi \Delta =m$$

Tenglama standart shaklda.

$$\frac{67\psi }{5}\Delta =m$$

Ikki tarafini 13,4\psi ga bo‘ling.

$$\frac{5\times \frac{67\psi }{5}\Delta }{67\psi }=\frac{5m}{67\psi }$$

13,4\psi ga bo'lish 13,4\psi ga ko'paytirishni bekor qiladi.

$$\Delta =\frac{5m}{67\psi }$$

m uchun yechish

$$m=\frac{67\Delta \psi }{5}$$

Yechim qadamlari

13,4 hosil qilish uchun 2 va 6,7 ni ko'paytirish.

$$m=13,4\psi \Delta$$