m=x-3/x-6+2 eching

$$m = \frac { x - 3 } { x - 6 } + 2$$

x uchun yechish

$$x=-\frac{3\left(2m-5\right)}{3-m}$$

$$m\neq 3$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x qiymati 6 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini x-6 ga ko'paytirish.

$$m\left(x-6\right)=x-3+\left(x-6\right)\times 2$$

m ga x-6 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$mx-6m=x-3+\left(x-6\right)\times 2$$

x-6 ga 2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$mx-6m=x-3+2x-12$$

3x ni olish uchun x va 2x ni birlashtirish.

$$mx-6m=3x-3-12$$

-15 olish uchun -3 dan 12 ni ayirish.

$$mx-6m=3x-15$$

Ikkala tarafdan 3x ni ayirish.

$$mx-6m-3x=-15$$

6m ni ikki tarafga qo’shing.

$$mx-3x=-15+6m$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(m-3\right)x=-15+6m$$

Tenglama standart shaklda.

$$\left(m-3\right)x=6m-15$$

Ikki tarafini m-3 ga bo‘ling.

$$\frac{\left(m-3\right)x}{m-3}=\frac{6m-15}{m-3}$$

m-3 ga bo'lish m-3 ga ko'paytirishni bekor qiladi.

$$x=\frac{6m-15}{m-3}$$

6m-15 ni m-3 ga bo'lish.

$$x=\frac{3\left(2m-5\right)}{m-3}$$

x qiymati 6 teng bo‘lmaydi.

$$x=\frac{3\left(2m-5\right)}{m-3}\text{, }x\neq 6$$

m uchun yechish

$$m=-\frac{3\left(5-x\right)}{x-6}$$

$$x\neq 6$$