kAROLA=x eching

$$k A R O L A = x$$

L uchun yechish (complex solution)

$$\left\{\begin{matrix}L=\frac{x}{ORkA^{2}}\text{, }&A\neq 0\text{ and }O\neq 0\text{ and }R\neq 0\text{ and }k\neq 0\\L\in \mathrm{C}\text{, }&\left(A=0\text{ or }O=0\text{ or }R=0\text{ or }k=0\right)\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

A^{2} hosil qilish uchun A va A ni ko'paytirish.

$$kA^{2}ROL=x$$

Tenglama standart shaklda.

$$ORkA^{2}L=x$$

Ikki tarafini kA^{2}RO ga bo‘ling.

$$\frac{ORkA^{2}L}{ORkA^{2}}=\frac{x}{ORkA^{2}}$$

kA^{2}RO ga bo'lish kA^{2}RO ga ko'paytirishni bekor qiladi.

$$L=\frac{x}{ORkA^{2}}$$

L uchun yechish

$$\left\{\begin{matrix}L=\frac{x}{ORkA^{2}}\text{, }&A\neq 0\text{ and }O\neq 0\text{ and }R\neq 0\text{ and }k\neq 0\\L\in \mathrm{R}\text{, }&\left(A=0\text{ or }O=0\text{ or }R=0\text{ or }k=0\right)\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

A^{2} hosil qilish uchun A va A ni ko'paytirish.

$$kA^{2}ROL=x$$

Tenglama standart shaklda.

$$ORkA^{2}L=x$$

Ikki tarafini kA^{2}RO ga bo‘ling.

$$\frac{ORkA^{2}L}{ORkA^{2}}=\frac{x}{ORkA^{2}}$$

kA^{2}RO ga bo'lish kA^{2}RO ga ko'paytirishni bekor qiladi.

$$L=\frac{x}{ORkA^{2}}$$

A uchun yechish (complex solution)

$$\left\{\begin{matrix}A=-L^{-\frac{1}{2}}O^{-\frac{1}{2}}R^{-\frac{1}{2}}k^{-\frac{1}{2}}\sqrt{x}\text{; }A=L^{-\frac{1}{2}}O^{-\frac{1}{2}}R^{-\frac{1}{2}}k^{-\frac{1}{2}}\sqrt{x}\text{, }&L\neq 0\text{ and }O\neq 0\text{ and }R\neq 0\text{ and }k\neq 0\\A\in \mathrm{C}\text{, }&\left(L=0\text{ or }O=0\text{ or }R=0\text{ or }k=0\right)\text{ and }x=0\end{matrix}\right,$$