if(x)=2(x+1)/4-x eching

$$i f ( x ) = \frac { 2 ( x + 1 ) } { 4 - x }$$

f uchun yechish

$$f=\frac{2\left(x+1\right)}{x\left(4i-ix\right)}$$

$$x\neq 4\text{ and }x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini -x+4 ga ko'paytirish.

$$ifx\left(-x+4\right)=2\left(x+1\right)$$

ifx ga -x+4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-ifx^{2}+4ifx=2\left(x+1\right)$$

2 ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-ifx^{2}+4ifx=2x+2$$

f'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(-ix^{2}+4ix\right)f=2x+2$$

Tenglama standart shaklda.

$$\left(4ix-ix^{2}\right)f=2x+2$$

Ikki tarafini 4ix-ix^{2} ga bo‘ling.

$$\frac{\left(4ix-ix^{2}\right)f}{4ix-ix^{2}}=\frac{2x+2}{4ix-ix^{2}}$$

4ix-ix^{2} ga bo'lish 4ix-ix^{2} ga ko'paytirishni bekor qiladi.

$$f=\frac{2x+2}{4ix-ix^{2}}$$

2+2x ni 4ix-ix^{2} ga bo'lish.

$$f=\frac{2\left(x+1\right)}{x\left(4i-ix\right)}$$

x uchun yechish

$$\left\{\begin{matrix}x=\frac{i\sqrt{1-6if-4f^{2}}+2f+i}{f}\text{; }x=\frac{-i\sqrt{1-6if-4f^{2}}+2f+i}{f}\text{, }&f\neq 0\\x=-1\text{, }&f=0\end{matrix}\right,$$