h4*|-15+13| eching

$$h 4 \cdot | - 15 + 13 |$$

Baholash

$$2h_{4}$$

Yechim qadamlari

-2 olish uchun -15 va 13'ni qo'shing.

$$h_{4}|-2|$$

a haqiqiy sonining mutloq qiymati qachon a\geq 0 bo‘lganda, a yoki qachon a<0 bo‘lganda -a. -2 ning mutloq qiymati 2 ga teng.

$$h_{4}\times 2$$

h_4 ga nisbatan hosilani topish

$$2$$

Derivativ ifodasidan foydalanish qadamlari

-2 olish uchun -15 va 13'ni qo'shing.

$$\frac{\mathrm{d}}{\mathrm{d}h_{4}}(h_{4}|-2|)$$

a haqiqiy sonining mutloq qiymati qachon a\geq 0 bo‘lganda, a yoki qachon a<0 bo‘lganda -a. -2 ning mutloq qiymati 2 ga teng.

$$\frac{\mathrm{d}}{\mathrm{d}h_{4}}(h_{4}\times 2)$$

ax^{n} hosilasi – nax^{n-1}.

$$2h_{4}^{1-1}$$

1 dan 1 ni ayirish.

$$2h_{4}^{0}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$2\times 1$$

Har qanday t sharti uchun t\times 1=t va 1t=t.

$$2$$