h(x)=-x^2-2x eching

$$h ( x ) = - x ^ { 2 } - 2 x$$

Omil

$$-x\left(x+2\right)$$

Yechim qadamlari

x omili.

$$x\left(-x-2\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-x^{2}-2x=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}}}{2\left(-1\right)}$$

\left(-2\right)^{2} ning kvadrat ildizini chiqarish.

$$x=\frac{-\left(-2\right)±2}{2\left(-1\right)}$$

-2 ning teskarisi 2 ga teng.

$$x=\frac{2±2}{2\left(-1\right)}$$

2 ni -1 marotabaga ko'paytirish.

$$x=\frac{2±2}{-2}$$

x=\frac{2±2}{-2} tenglamasini yeching, bunda ± musbat. 2 ni 2 ga qo'shish.

$$x=\frac{4}{-2}$$

4 ni -2 ga bo'lish.

$$x=-2$$

x=\frac{2±2}{-2} tenglamasini yeching, bunda ± manfiy. 2 dan 2 ni ayirish.

$$x=\frac{0}{-2}$$

0 ni -2 ga bo'lish.

$$x=0$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -2 ga va x_{2} uchun 0 ga bo‘ling.

$$-x^{2}-2x=-\left(x-\left(-2\right)\right)x$$

p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.

$$-x^{2}-2x=-\left(x+2\right)x$$

Baholash

$$-x\left(x+2\right)$$