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\left(\sqrt{3}\right)^{2}x^{2}+6\sqrt{3}x+9-11
\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(\sqrt{3}x+3\right)^{2} kengaytirilishi uchun ishlating.
3x^{2}+6\sqrt{3}x+9-11
\sqrt{3} kvadrati – 3.
3x^{2}+6\sqrt{3}x-2
-2 olish uchun 9 dan 11 ni ayirish.
\left(\sqrt{3}\right)^{2}x^{2}+6\sqrt{3}x+9-11
\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(\sqrt{3}x+3\right)^{2} kengaytirilishi uchun ishlating.
3x^{2}+6\sqrt{3}x+9-11
\sqrt{3} kvadrati – 3.
3x^{2}+6\sqrt{3}x-2
-2 olish uchun 9 dan 11 ni ayirish.