h=r*1/1+frac{s{t}} eching

$$h = r \cdot \frac { 1 } { 1 + \frac { s } { t } }$$

r uchun yechish

$$r=\frac{h\left(s+t\right)}{t}$$

$$s\neq -t\text{ and }t\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ifodalarni qo‘shish yoki ayirish uchun ularni yoyib, maxrajlarini bir xil qiling. 1 ni \frac{t}{t} marotabaga ko'paytirish.

$$h=r\times \frac{1}{\frac{t}{t}+\frac{s}{t}}$$

\frac{t}{t} va \frac{s}{t} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$h=r\times \frac{1}{\frac{t+s}{t}}$$

1 ni \frac{t+s}{t} ga bo'lish 1 ga k'paytirish \frac{t+s}{t} ga qaytarish.

$$h=r\times \frac{t}{t+s}$$

r\times \frac{t}{t+s} ni yagona kasrga aylantiring.

$$h=\frac{rt}{t+s}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\frac{rt}{t+s}=h$$

Tenglamaning ikkala tarafini s+t ga ko'paytirish.

$$rt=h\left(s+t\right)$$

h ga s+t ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$rt=hs+ht$$

Tenglama standart shaklda.

$$tr=hs+ht$$

Ikki tarafini t ga bo‘ling.

$$\frac{tr}{t}=\frac{h\left(s+t\right)}{t}$$

t ga bo'lish t ga ko'paytirishni bekor qiladi.

$$r=\frac{h\left(s+t\right)}{t}$$

h uchun yechish

$$h=\frac{rt}{s+t}$$

$$s\neq -t\text{ and }t\neq 0$$