h=frac{sqrt{3x}}{2} eching

$$h = \frac { \sqrt { 3 x } } { 2 }$$

x uchun yechish

$$x=\frac{4h^{2}}{3}$$

$$h\geq 0$$

Ildizli tenglamalarni yechish qadamlari

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\frac{\sqrt{3x}}{2}=h$$

Ikkala tarafini 2 ga ko‘paytiring.

$$\frac{\frac{1}{2}\sqrt{3x}}{\frac{1}{2}}=\frac{h}{\frac{1}{2}}$$

\frac{1}{2} ga bo'lish \frac{1}{2} ga ko'paytirishni bekor qiladi.

$$\sqrt{3x}=\frac{h}{\frac{1}{2}}$$

h ni \frac{1}{2} ga bo'lish h ga k'paytirish \frac{1}{2} ga qaytarish.

$$\sqrt{3x}=2h$$

Tenglamaning ikkala taraf kvadratini chiqarish.

$$3x=4h^{2}$$

Ikki tarafini 3 ga bo‘ling.

$$\frac{3x}{3}=\frac{4h^{2}}{3}$$

3 ga bo'lish 3 ga ko'paytirishni bekor qiladi.

$$x=\frac{4h^{2}}{3}$$

x uchun yechish (complex solution)

$$x=\frac{4h^{2}}{3}$$

$$|\frac{arg(h^{2})}{2}-arg(h)|<\pi \text{ or }h=0$$

h uchun yechish

$$h=\frac{\sqrt{3x}}{2}$$

$$x\geq 0$$