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-\frac{1}{3}\left(x^{2}-10x+25\right)-1
\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(x-5\right)^{2} kengaytirilishi uchun ishlating.
-\frac{1}{3}x^{2}+\frac{10}{3}x-\frac{25}{3}-1
-\frac{1}{3} ga x^{2}-10x+25 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
-\frac{1}{3}x^{2}+\frac{10}{3}x-\frac{28}{3}
-\frac{28}{3} olish uchun -\frac{25}{3} dan 1 ni ayirish.
-\frac{1}{3}\left(x^{2}-10x+25\right)-1
\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(x-5\right)^{2} kengaytirilishi uchun ishlating.
-\frac{1}{3}x^{2}+\frac{10}{3}x-\frac{25}{3}-1
-\frac{1}{3} ga x^{2}-10x+25 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
-\frac{1}{3}x^{2}+\frac{10}{3}x-\frac{28}{3}
-\frac{28}{3} olish uchun -\frac{25}{3} dan 1 ni ayirish.