g(x)=(x^2+4)^3 eching

$$g ( x ) = ( x ^ { 2 } + 4 ) ^ { 3 }$$

Baholash

$$\left(x^{2}+4\right)^{3}$$

Yechim qadamlari

\left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} binom teoremasini \left(x^{2}+4\right)^{3} kengaytirilishi uchun ishlating.

$$\left(x^{2}\right)^{3}+12\left(x^{2}\right)^{2}+48x^{2}+64$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 3 ni ko‘paytirib, 6 ni oling.

$$x^{6}+12\left(x^{2}\right)^{2}+48x^{2}+64$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$x^{6}+12x^{4}+48x^{2}+64$$

Kengaytirish

$$x^{6}+12x^{4}+48x^{2}+64$$

Yechim qadamlari

\left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} binom teoremasini \left(x^{2}+4\right)^{3} kengaytirilishi uchun ishlating.

$$\left(x^{2}\right)^{3}+12\left(x^{2}\right)^{2}+48x^{2}+64$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 3 ni ko‘paytirib, 6 ni oling.

$$x^{6}+12\left(x^{2}\right)^{2}+48x^{2}+64$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$x^{6}+12x^{4}+48x^{2}+64$$