fy=(x-1)(x+1)(2-x) eching

$$f y = ( x - 1 ) ( x + 1 ) ( 2 - x )$$

f uchun yechish

$$\left\{\begin{matrix}f=\frac{\left(2-x\right)\left(x^{2}-1\right)}{y}\text{, }&y\neq 0\\f\in \mathrm{R}\text{, }&\left(x=2\text{ or }|x|=1\right)\text{ and }y=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x-1 ga x+1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$fy=\left(x^{2}-1\right)\left(2-x\right)$$

x^{2}-1 ga 2-x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$fy=2x^{2}-x^{3}-2+x$$

Tenglama standart shaklda.

$$yf=-x^{3}+2x^{2}+x-2$$

Ikki tarafini y ga bo‘ling.

$$\frac{yf}{y}=\frac{\left(2-x\right)\left(x^{2}-1\right)}{y}$$

y ga bo'lish y ga ko'paytirishni bekor qiladi.

$$f=\frac{\left(2-x\right)\left(x^{2}-1\right)}{y}$$