f(x)^-1=x^3+1/2 eching

$$f ( x ) ^ { - 1 } = \frac { x ^ { 3 } + 1 } { 2 }$$

f uchun yechish

$$f=\frac{x\left(x^{3}+1\right)}{2}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 2 ga ko'paytirish.

$$2fx^{-1}=x^{3}+1$$

Shartlarni qayta saralash.

$$2\times \frac{1}{x}f=x^{3}+1$$

Tenglamaning ikkala tarafini x ga ko'paytirish.

$$2\times 1f=xx^{3}+x$$

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 1 va 3 ni qo‘shib, 4 ni oling.

$$2\times 1f=x^{4}+x$$

2 hosil qilish uchun 2 va 1 ni ko'paytirish.

$$2f=x^{4}+x$$

Ikki tarafini 2 ga bo‘ling.

$$\frac{2f}{2}=\frac{x^{4}+x}{2}$$

2 ga bo'lish 2 ga ko'paytirishni bekor qiladi.

$$f=\frac{x^{4}+x}{2}$$