g uchun yechish
g=\frac{x^{2}}{6}-x+\frac{5}{3}-\frac{1}{3x}
x\neq 0
Grafik
Viktorina
Linear Equation
5xshash muammolar:
f ( x ) = x ^ { 3 } - 6 x ^ { 2 } + 11 x - 6 g ( x ) = x + 2
Baham ko'rish
Klipbordga nusxa olish
-6x^{2}+11x-6gx=x+2-x^{3}
Ikkala tarafdan x^{3} ni ayirish.
11x-6gx=x+2-x^{3}+6x^{2}
6x^{2} ni ikki tarafga qo’shing.
-6gx=x+2-x^{3}+6x^{2}-11x
Ikkala tarafdan 11x ni ayirish.
-6gx=-10x+2-x^{3}+6x^{2}
-10x ni olish uchun x va -11x ni birlashtirish.
\left(-6x\right)g=2-10x+6x^{2}-x^{3}
Tenglama standart shaklda.
\frac{\left(-6x\right)g}{-6x}=\frac{2-10x+6x^{2}-x^{3}}{-6x}
Ikki tarafini -6x ga bo‘ling.
g=\frac{2-10x+6x^{2}-x^{3}}{-6x}
-6x ga bo'lish -6x ga ko'paytirishni bekor qiladi.
g=\frac{x^{2}}{6}-x+\frac{5}{3}-\frac{1}{3x}
-10x+2-x^{3}+6x^{2} ni -6x ga bo'lish.
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