f(x)=x^3-6x^2+11x-6g(x)=x+2 eching

$$f ( x ) = x ^ { 3 } - 6 x ^ { 2 } + 11 x - 6 g ( x ) = x + 2$$

g uchun yechish

$$g=\frac{x^{2}}{6}-x+\frac{5}{3}-\frac{1}{3x}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan x^{3} ni ayirish.

$$-6x^{2}+11x-6gx=x+2-x^{3}$$

6x^{2} ni ikki tarafga qo’shing.

$$11x-6gx=x+2-x^{3}+6x^{2}$$

Ikkala tarafdan 11x ni ayirish.

$$-6gx=x+2-x^{3}+6x^{2}-11x$$

-10x ni olish uchun x va -11x ni birlashtirish.

$$-6gx=-10x+2-x^{3}+6x^{2}$$

Tenglama standart shaklda.

$$\left(-6x\right)g=2-10x+6x^{2}-x^{3}$$

Ikki tarafini -6x ga bo‘ling.

$$\frac{\left(-6x\right)g}{-6x}=\frac{2-10x+6x^{2}-x^{3}}{-6x}$$

-6x ga bo'lish -6x ga ko'paytirishni bekor qiladi.

$$g=\frac{2-10x+6x^{2}-x^{3}}{-6x}$$

-10x+2-x^{3}+6x^{2} ni -6x ga bo'lish.

$$g=\frac{x^{2}}{6}-x+\frac{5}{3}-\frac{1}{3x}$$