f(x)=x^2-3xyg(x)=-x^2+5x eching

$$f ( x ) = x ^ { 2 } - 3 x y g ( x ) = - x ^ { 2 } + 5 x$$

g uchun yechish

$$\left\{\begin{matrix}g=\frac{2x-5}{3xy}\text{, }&y\neq 0\text{ and }x\neq 0\\g\in \mathrm{R}\text{, }&x=0\text{ or }\left(x=\frac{5}{2}\text{ and }y=0\right)\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x^{2} hosil qilish uchun x va x ni ko'paytirish.

$$x^{2}-3x^{2}yg=-x^{2}+5x$$

Ikkala tarafdan x^{2} ni ayirish.

$$-3x^{2}yg=-x^{2}+5x-x^{2}$$

-2x^{2} ni olish uchun -x^{2} va -x^{2} ni birlashtirish.

$$-3x^{2}yg=-2x^{2}+5x$$

Tenglama standart shaklda.

$$\left(-3yx^{2}\right)g=5x-2x^{2}$$

Ikki tarafini -3x^{2}y ga bo‘ling.

$$\frac{\left(-3yx^{2}\right)g}{-3yx^{2}}=\frac{x\left(5-2x\right)}{-3yx^{2}}$$

-3x^{2}y ga bo'lish -3x^{2}y ga ko'paytirishni bekor qiladi.

$$g=\frac{x\left(5-2x\right)}{-3yx^{2}}$$

x\left(5-2x\right) ni -3x^{2}y ga bo'lish.

$$g=-\frac{5-2x}{3xy}$$

x uchun yechish

$$\left\{\begin{matrix}\\x=0\text{, }&\text{unconditionally}\\x=\frac{5}{2-3gy}\text{, }&g=0\text{ or }y\neq \frac{2}{3g}\end{matrix}\right,$$