f(x)=x^2+3x-4quadn^primey_{1}7 eching

$$f ( x ) = x ^ { 2 } + 3 x - 4 \quad n ^ { \prime } y _ { 1 } 7$$

f uchun yechish (complex solution)

$$\left\{\begin{matrix}\\f=x+3\text{, }&\text{unconditionally}\\f\in \mathrm{C}\text{, }&x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

28 hosil qilish uchun 4 va 7 ni ko'paytirish.

$$fx=x^{2}+3x-28\frac{\mathrm{d}}{\mathrm{d}x}(n)y_{1}$$

Tenglama standart shaklda.

$$xf=x^{2}+3x$$

Ikki tarafini x ga bo‘ling.

$$\frac{xf}{x}=\frac{x\left(x+3\right)}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$f=\frac{x\left(x+3\right)}{x}$$

x\left(3+x\right) ni x ga bo'lish.

$$f=x+3$$

f uchun yechish

$$\left\{\begin{matrix}f=x+3\text{, }&x\neq 0\\f\in \mathrm{R}\text{, }&x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

28 hosil qilish uchun 4 va 7 ni ko'paytirish.

$$fx=x^{2}+3x-28\frac{\mathrm{d}}{\mathrm{d}x}(n)y_{1}$$

Tenglama standart shaklda.

$$xf=x^{2}+3x$$

Ikki tarafini x ga bo‘ling.

$$\frac{xf}{x}=\frac{x\left(x+3\right)}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$f=\frac{x\left(x+3\right)}{x}$$

x\left(3+x\right) ni x ga bo'lish.

$$f=x+3$$

n uchun yechish (complex solution)

$$n\in \mathrm{C}$$

$$x=0\text{ or }f=x+3$$

n uchun yechish

$$n\in \mathrm{R}$$

$$x=0\text{ or }f=x+3$$