f(x)=x^2+1quadg(x)=-4x-1 eching

$$f ( x ) = x ^ { 2 } + 1 \quad g ( x ) = - 4 x - 1$$

g uchun yechish

$$g=-x-4-\frac{1}{x}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan x^{2} ni ayirish.

$$1gx=-4x-1-x^{2}$$

Shartlarni qayta saralash.

$$gx=-x^{2}-4x-1$$

Tenglama standart shaklda.

$$xg=-x^{2}-4x-1$$

Ikki tarafini x ga bo‘ling.

$$\frac{xg}{x}=\frac{-x^{2}-4x-1}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$g=\frac{-x^{2}-4x-1}{x}$$

-x^{2}-4x-1 ni x ga bo'lish.

$$g=-x-4-\frac{1}{x}$$

x uchun yechish (complex solution)

$$x=\frac{\sqrt{\left(g+2\right)\left(g+6\right)}-g-4}{2}$$

$$x=\frac{-\sqrt{\left(g+2\right)\left(g+6\right)}-g-4}{2}$$

x uchun yechish

$$x=\frac{\sqrt{\left(g+2\right)\left(g+6\right)}-g-4}{2}$$

$$x=\frac{-\sqrt{\left(g+2\right)\left(g+6\right)}-g-4}{2}\text{, }g\leq -6\text{ or }g\geq -2$$