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7x^{2}+x-1=0
Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.
x=\frac{-1±\sqrt{1^{2}-4\times 7\left(-1\right)}}{2\times 7}
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x=\frac{-1±\sqrt{1-4\times 7\left(-1\right)}}{2\times 7}
1 kvadratini chiqarish.
x=\frac{-1±\sqrt{1-28\left(-1\right)}}{2\times 7}
-4 ni 7 marotabaga ko'paytirish.
x=\frac{-1±\sqrt{1+28}}{2\times 7}
-28 ni -1 marotabaga ko'paytirish.
x=\frac{-1±\sqrt{29}}{2\times 7}
1 ni 28 ga qo'shish.
x=\frac{-1±\sqrt{29}}{14}
2 ni 7 marotabaga ko'paytirish.
x=\frac{\sqrt{29}-1}{14}
x=\frac{-1±\sqrt{29}}{14} tenglamasini yeching, bunda ± musbat. -1 ni \sqrt{29} ga qo'shish.
x=\frac{-\sqrt{29}-1}{14}
x=\frac{-1±\sqrt{29}}{14} tenglamasini yeching, bunda ± manfiy. -1 dan \sqrt{29} ni ayirish.
7x^{2}+x-1=7\left(x-\frac{\sqrt{29}-1}{14}\right)\left(x-\frac{-\sqrt{29}-1}{14}\right)
ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-1+\sqrt{29}}{14} ga va x_{2} uchun \frac{-1-\sqrt{29}}{14} ga bo‘ling.