f(x)=6(x-8)(x+3)^3 eching

$$f ( x ) = 6 ( x - 8 ) ( x + 3 ) ^ { 3 }$$

Baholash

$$6\left(x-8\right)\left(x+3\right)^{3}$$

Yechim qadamlari

\left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} binom teoremasini \left(x+3\right)^{3} kengaytirilishi uchun ishlating.

$$6\left(x-8\right)\left(x^{3}+9x^{2}+27x+27\right)$$

6 ga x-8 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(6x-48\right)\left(x^{3}+9x^{2}+27x+27\right)$$

6x-48 ga x^{3}+9x^{2}+27x+27 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$6x^{4}+6x^{3}-270x^{2}-1134x-1296$$

Kengaytirish

$$6x^{4}+6x^{3}-270x^{2}-1134x-1296$$

Yechim qadamlari

\left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} binom teoremasini \left(x+3\right)^{3} kengaytirilishi uchun ishlating.

$$6\left(x-8\right)\left(x^{3}+9x^{2}+27x+27\right)$$

6 ga x-8 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(6x-48\right)\left(x^{3}+9x^{2}+27x+27\right)$$

6x-48 ga x^{3}+9x^{2}+27x+27 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$6x^{4}+6x^{3}-270x^{2}-1134x-1296$$