f(x)=3x^2+7x-8 eching

$$f ( x ) = 3 x ^ { 2 } + 7 x - 8$$

Omil

$$3\left(x-\frac{-\sqrt{145}-7}{6}\right)\left(x-\frac{\sqrt{145}-7}{6}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$3x^{2}+7x-8=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-7±\sqrt{7^{2}-4\times 3\left(-8\right)}}{2\times 3}$$

7 kvadratini chiqarish.

$$x=\frac{-7±\sqrt{49-4\times 3\left(-8\right)}}{2\times 3}$$

-4 ni 3 marotabaga ko'paytirish.

$$x=\frac{-7±\sqrt{49-12\left(-8\right)}}{2\times 3}$$

-12 ni -8 marotabaga ko'paytirish.

$$x=\frac{-7±\sqrt{49+96}}{2\times 3}$$

49 ni 96 ga qo'shish.

$$x=\frac{-7±\sqrt{145}}{2\times 3}$$

2 ni 3 marotabaga ko'paytirish.

$$x=\frac{-7±\sqrt{145}}{6}$$

x=\frac{-7±\sqrt{145}}{6} tenglamasini yeching, bunda ± musbat. -7 ni \sqrt{145} ga qo'shish.

$$x=\frac{\sqrt{145}-7}{6}$$

x=\frac{-7±\sqrt{145}}{6} tenglamasini yeching, bunda ± manfiy. -7 dan \sqrt{145} ni ayirish.

$$x=\frac{-\sqrt{145}-7}{6}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-7+\sqrt{145}}{6} ga va x_{2} uchun \frac{-7-\sqrt{145}}{6} ga bo‘ling.

$$3x^{2}+7x-8=3\left(x-\frac{\sqrt{145}-7}{6}\right)\left(x-\frac{-\sqrt{145}-7}{6}\right)$$

Baholash

$$3x^{2}+7x-8$$