f(x)=2x-1h(x)=-5/x-1 eching

$$f ( x ) = 2 x - 1 h ( x ) = - \frac { 5 } { x - 1 }$$

h uchun yechish

$$h=-\frac{2x^{2}-2x+5}{x\left(1-x\right)}$$

$$x\neq 1\text{ and }x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini x-1 ga ko'paytirish.

$$2x\left(x-1\right)-hx\left(x-1\right)=-5$$

2x ga x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2x^{2}-2x-hx\left(x-1\right)=-5$$

-hx ga x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2x^{2}-2x-hx^{2}+xh=-5$$

Ikkala tarafdan 2x^{2} ni ayirish.

$$-2x-hx^{2}+xh=-5-2x^{2}$$

2x ni ikki tarafga qo’shing.

$$-hx^{2}+xh=-5-2x^{2}+2x$$

h'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(-x^{2}+x\right)h=-5-2x^{2}+2x$$

Tenglama standart shaklda.

$$\left(x-x^{2}\right)h=-2x^{2}+2x-5$$

Ikki tarafini -x^{2}+x ga bo‘ling.

$$\frac{\left(x-x^{2}\right)h}{x-x^{2}}=\frac{-2x^{2}+2x-5}{x-x^{2}}$$

-x^{2}+x ga bo'lish -x^{2}+x ga ko'paytirishni bekor qiladi.

$$h=\frac{-2x^{2}+2x-5}{x-x^{2}}$$

-5-2x^{2}+2x ni -x^{2}+x ga bo'lish.

$$h=\frac{-2x^{2}+2x-5}{x\left(1-x\right)}$$

x uchun yechish (complex solution)

$$x=\frac{\sqrt{-\left(2-h\right)\left(h+18\right)}-h+2}{2\left(2-h\right)}$$

$$x=\frac{-\sqrt{-\left(2-h\right)\left(h+18\right)}-h+2}{2\left(2-h\right)}\text{, }h\neq 2$$

x uchun yechish

$$x=\frac{\sqrt{-\left(2-h\right)\left(h+18\right)}-h+2}{2\left(2-h\right)}$$

$$x=\frac{-\sqrt{-\left(2-h\right)\left(h+18\right)}-h+2}{2\left(2-h\right)}\text{, }h>2\text{ or }h\leq -18$$