f(x)=1/1-x^2*g(x)=x^2 eching

$$f ( x ) = \frac { 1 } { 1 - x ^ { 2 } } \cdot g ( x ) = x ^ { 2 }$$

g uchun yechish

$$\left\{\begin{matrix}g=x-x^{3}\text{, }&|x|\neq 1\\g\in \mathrm{R}\text{, }&x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini \left(x-1\right)\left(-x-1\right) ga ko'paytirish.

$$1gx=\left(x-1\right)\left(-x-1\right)x^{2}$$

x-1 ga -x-1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$1gx=\left(-x^{2}+1\right)x^{2}$$

-x^{2}+1 ga x^{2} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$1gx=-x^{4}+x^{2}$$

Shartlarni qayta saralash.

$$gx=-x^{4}+x^{2}$$

Tenglama standart shaklda.

$$xg=x^{2}-x^{4}$$

Ikki tarafini x ga bo‘ling.

$$\frac{xg}{x}=\frac{x^{2}-x^{4}}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$g=\frac{x^{2}-x^{4}}{x}$$

-x^{4}+x^{2} ni x ga bo'lish.

$$g=x-x^{3}$$