f(a+h)-F(a)=7-6x+4x^2 eching

$$f ( a + h ) - F ( a ) = 7 - 6 x + 4 x ^ { 2 }$$

F uchun yechish

$$\left\{\begin{matrix}F=\frac{-4x^{2}+6x+af+fh-7}{a}\text{, }&a\neq 0\\F\in \mathrm{R}\text{, }&f=-\frac{-4x^{2}+6x-7}{h}\text{ and }a=0\text{ and }h\neq 0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

f ga a+h ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$fa+fh-Fa=7-6x+4x^{2}$$

Ikkala tarafdan fa ni ayirish.

$$fh-Fa=7-6x+4x^{2}-fa$$

Ikkala tarafdan fh ni ayirish.

$$-Fa=7-6x+4x^{2}-fa-fh$$

Tenglama standart shaklda.

$$\left(-a\right)F=4x^{2}-6x-af-fh+7$$

Ikki tarafini -a ga bo‘ling.

$$\frac{\left(-a\right)F}{-a}=\frac{4x^{2}-6x-af-fh+7}{-a}$$

-a ga bo'lish -a ga ko'paytirishni bekor qiladi.

$$F=\frac{4x^{2}-6x-af-fh+7}{-a}$$

7-6x+4x^{2}-fa-fh ni -a ga bo'lish.

$$F=-\frac{4x^{2}-6x-af-fh+7}{a}$$

a uchun yechish

$$\left\{\begin{matrix}a=-\frac{-4x^{2}+6x+fh-7}{f-F}\text{, }&f\neq F\\a\in \mathrm{R}\text{, }&f=\frac{4x^{2}-6x+7}{h}\text{ and }F=\frac{4x^{2}-6x+7}{h}\text{ and }h\neq 0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

f ga a+h ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$fa+fh-Fa=7-6x+4x^{2}$$

Ikkala tarafdan fh ni ayirish.

$$fa-Fa=7-6x+4x^{2}-fh$$

a'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(f-F\right)a=7-6x+4x^{2}-fh$$

Tenglama standart shaklda.

$$\left(f-F\right)a=4x^{2}-6x-fh+7$$

Ikki tarafini f-F ga bo‘ling.

$$\frac{\left(f-F\right)a}{f-F}=\frac{4x^{2}-6x-fh+7}{f-F}$$

f-F ga bo'lish f-F ga ko'paytirishni bekor qiladi.

$$a=\frac{4x^{2}-6x-fh+7}{f-F}$$