dx_{13}=sqrt{(5)^2+(-12)^2} eching

$$d x _ { 13 } = \sqrt { ( 5 ) ^ { 2 } + ( - 12 ) ^ { 2 } }$$

d uchun yechish

$$d=\frac{13}{x_{13}}$$

$$x_{13}\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini 5 ga hisoblang va 25 ni qiymatni oling.

$$dx_{13}=\sqrt{25+\left(-12\right)^{2}}$$

2 daraja ko‘rsatkichini -12 ga hisoblang va 144 ni qiymatni oling.

$$dx_{13}=\sqrt{25+144}$$

169 olish uchun 25 va 144'ni qo'shing.

$$dx_{13}=\sqrt{169}$$

169 ning kvadrat ildizini hisoblab, 13 natijaga ega bo‘ling.

$$dx_{13}=13$$

Tenglama standart shaklda.

$$x_{13}d=13$$

Ikki tarafini x_{13} ga bo‘ling.

$$\frac{x_{13}d}{x_{13}}=\frac{13}{x_{13}}$$

x_{13} ga bo'lish x_{13} ga ko'paytirishni bekor qiladi.

$$d=\frac{13}{x_{13}}$$

x_13 uchun yechish

$$x_{13}=\frac{13}{d}$$

$$d\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini 5 ga hisoblang va 25 ni qiymatni oling.

$$dx_{13}=\sqrt{25+\left(-12\right)^{2}}$$

2 daraja ko‘rsatkichini -12 ga hisoblang va 144 ni qiymatni oling.

$$dx_{13}=\sqrt{25+144}$$

169 olish uchun 25 va 144'ni qo'shing.

$$dx_{13}=\sqrt{169}$$

169 ning kvadrat ildizini hisoblab, 13 natijaga ega bo‘ling.

$$dx_{13}=13$$

Ikki tarafini d ga bo‘ling.

$$\frac{dx_{13}}{d}=\frac{13}{d}$$

d ga bo'lish d ga ko'paytirishni bekor qiladi.

$$x_{13}=\frac{13}{d}$$