dh(t)=2t^2-4r eching

$$d h ( t ) = 2 t ^ { 2 } - 4 r$$

r uchun yechish

$$r=\frac{t^{2}}{2}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$2t^{2}-4r=\frac{\mathrm{d}}{\mathrm{d}h}(t)$$

Ikkala tarafdan 2t^{2} ni ayirish.

$$-4r=\frac{\mathrm{d}}{\mathrm{d}h}(t)-2t^{2}$$

Tenglama standart shaklda.

$$-4r=-2t^{2}$$

Ikki tarafini -4 ga bo‘ling.

$$\frac{-4r}{-4}=-\frac{2t^{2}}{-4}$$

-4 ga bo'lish -4 ga ko'paytirishni bekor qiladi.

$$r=-\frac{2t^{2}}{-4}$$

-2t^{2} ni -4 ga bo'lish.

$$r=\frac{t^{2}}{2}$$

h uchun yechish

$$h\in \mathrm{R}$$

$$r=\frac{t^{2}}{2}$$