dh=(15t+6)dt eching

$$d h = ( 15 t + 6 ) d t$$

d uchun yechish (complex solution)

$$\left\{\begin{matrix}\\d=0\text{, }&\text{unconditionally}\\d\in \mathrm{C}\text{, }&h=3t\left(5t+2\right)\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

15t+6 ga d ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$dh=\left(15td+6d\right)t$$

15td+6d ga t ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$dh=15dt^{2}+6dt$$

Ikkala tarafdan 15dt^{2} ni ayirish.

$$dh-15dt^{2}=6dt$$

Ikkala tarafdan 6dt ni ayirish.

$$dh-15dt^{2}-6dt=0$$

d'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(h-15t^{2}-6t\right)d=0$$

Tenglama standart shaklda.

$$\left(h-6t-15t^{2}\right)d=0$$

0 ni -15t^{2}-6t+h ga bo'lish.

$$d=0$$

h uchun yechish (complex solution)

$$\left\{\begin{matrix}\\h=3t\left(5t+2\right)\text{, }&\text{unconditionally}\\h\in \mathrm{C}\text{, }&d=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

15t+6 ga d ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$dh=\left(15td+6d\right)t$$

15td+6d ga t ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$dh=15dt^{2}+6dt$$

Ikki tarafini d ga bo‘ling.

$$\frac{dh}{d}=\frac{3dt\left(5t+2\right)}{d}$$

d ga bo'lish d ga ko'paytirishni bekor qiladi.

$$h=\frac{3dt\left(5t+2\right)}{d}$$

3dt\left(2+5t\right) ni d ga bo'lish.

$$h=3t\left(5t+2\right)$$

d uchun yechish

$$\left\{\begin{matrix}\\d=0\text{, }&\text{unconditionally}\\d\in \mathrm{R}\text{, }&h=3t\left(5t+2\right)\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

15t+6 ga d ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$dh=\left(15td+6d\right)t$$

15td+6d ga t ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$dh=15dt^{2}+6dt$$

Ikkala tarafdan 15dt^{2} ni ayirish.

$$dh-15dt^{2}=6dt$$

Ikkala tarafdan 6dt ni ayirish.

$$dh-15dt^{2}-6dt=0$$

d'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(h-15t^{2}-6t\right)d=0$$

Tenglama standart shaklda.

$$\left(h-6t-15t^{2}\right)d=0$$

0 ni -15t^{2}-6t+h ga bo'lish.

$$d=0$$

h uchun yechish

$$\left\{\begin{matrix}\\h=3t\left(5t+2\right)\text{, }&\text{unconditionally}\\h\in \mathrm{R}\text{, }&d=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

15t+6 ga d ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$dh=\left(15td+6d\right)t$$

15td+6d ga t ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$dh=15dt^{2}+6dt$$

Ikki tarafini d ga bo‘ling.

$$\frac{dh}{d}=\frac{3dt\left(5t+2\right)}{d}$$

d ga bo'lish d ga ko'paytirishni bekor qiladi.

$$h=\frac{3dt\left(5t+2\right)}{d}$$

3dt\left(2+5t\right) ni d ga bo'lish.

$$h=3t\left(5t+2\right)$$