ax^2+bx=0 eching

$$a x ^ { 2 } + b x = 0$$

a uchun yechish (complex solution)

$$\left\{\begin{matrix}a=-\frac{b}{x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan bx ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$ax^{2}=-bx$$

Tenglama standart shaklda.

$$x^{2}a=-bx$$

Ikki tarafini x^{2} ga bo‘ling.

$$\frac{x^{2}a}{x^{2}}=-\frac{bx}{x^{2}}$$

x^{2} ga bo'lish x^{2} ga ko'paytirishni bekor qiladi.

$$a=-\frac{bx}{x^{2}}$$

-bx ni x^{2} ga bo'lish.

$$a=-\frac{b}{x}$$

b uchun yechish (complex solution)

$$\left\{\begin{matrix}\\b=-ax\text{, }&\text{unconditionally}\\b\in \mathrm{C}\text{, }&x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan ax^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$bx=-ax^{2}$$

Tenglama standart shaklda.

$$xb=-ax^{2}$$

Ikki tarafini x ga bo‘ling.

$$\frac{xb}{x}=-\frac{ax^{2}}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$b=-\frac{ax^{2}}{x}$$

-ax^{2} ni x ga bo'lish.

$$b=-ax$$

a uchun yechish

$$\left\{\begin{matrix}a=-\frac{b}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan bx ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$ax^{2}=-bx$$

Tenglama standart shaklda.

$$x^{2}a=-bx$$

Ikki tarafini x^{2} ga bo‘ling.

$$\frac{x^{2}a}{x^{2}}=-\frac{bx}{x^{2}}$$

x^{2} ga bo'lish x^{2} ga ko'paytirishni bekor qiladi.

$$a=-\frac{bx}{x^{2}}$$

-bx ni x^{2} ga bo'lish.

$$a=-\frac{b}{x}$$

b uchun yechish

$$\left\{\begin{matrix}\\b=-ax\text{, }&\text{unconditionally}\\b\in \mathrm{R}\text{, }&x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan ax^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$bx=-ax^{2}$$

Tenglama standart shaklda.

$$xb=-ax^{2}$$

Ikki tarafini x ga bo‘ling.

$$\frac{xb}{x}=-\frac{ax^{2}}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$b=-\frac{ax^{2}}{x}$$

-ax^{2} ni x ga bo'lish.

$$b=-ax$$