a uchun yechish (complex solution)
\left\{\begin{matrix}a=-\frac{bx+c}{x^{2}}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&c=0\text{ and }x=0\end{matrix}\right,
b uchun yechish (complex solution)
\left\{\begin{matrix}b=-ax-\frac{c}{x}\text{, }&x\neq 0\\b\in \mathrm{C}\text{, }&c=0\text{ and }x=0\end{matrix}\right,
a uchun yechish
\left\{\begin{matrix}a=-\frac{bx+c}{x^{2}}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&c=0\text{ and }x=0\end{matrix}\right,
b uchun yechish
\left\{\begin{matrix}b=-ax-\frac{c}{x}\text{, }&x\neq 0\\b\in \mathrm{R}\text{, }&c=0\text{ and }x=0\end{matrix}\right,
Grafik
Baham ko'rish
Klipbordga nusxa olish
ax^{2}+c=-bx
Ikkala tarafdan bx ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.
ax^{2}=-bx-c
Ikkala tarafdan c ni ayirish.
x^{2}a=-bx-c
Tenglama standart shaklda.
\frac{x^{2}a}{x^{2}}=\frac{-bx-c}{x^{2}}
Ikki tarafini x^{2} ga bo‘ling.
a=\frac{-bx-c}{x^{2}}
x^{2} ga bo'lish x^{2} ga ko'paytirishni bekor qiladi.
a=-\frac{bx+c}{x^{2}}
-bx-c ni x^{2} ga bo'lish.
bx+c=-ax^{2}
Ikkala tarafdan ax^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.
bx=-ax^{2}-c
Ikkala tarafdan c ni ayirish.
xb=-ax^{2}-c
Tenglama standart shaklda.
\frac{xb}{x}=\frac{-ax^{2}-c}{x}
Ikki tarafini x ga bo‘ling.
b=\frac{-ax^{2}-c}{x}
x ga bo'lish x ga ko'paytirishni bekor qiladi.
b=-ax-\frac{c}{x}
-ax^{2}-c ni x ga bo'lish.
ax^{2}+c=-bx
Ikkala tarafdan bx ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.
ax^{2}=-bx-c
Ikkala tarafdan c ni ayirish.
x^{2}a=-bx-c
Tenglama standart shaklda.
\frac{x^{2}a}{x^{2}}=\frac{-bx-c}{x^{2}}
Ikki tarafini x^{2} ga bo‘ling.
a=\frac{-bx-c}{x^{2}}
x^{2} ga bo'lish x^{2} ga ko'paytirishni bekor qiladi.
a=-\frac{bx+c}{x^{2}}
-bx-c ni x^{2} ga bo'lish.
bx+c=-ax^{2}
Ikkala tarafdan ax^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.
bx=-ax^{2}-c
Ikkala tarafdan c ni ayirish.
xb=-ax^{2}-c
Tenglama standart shaklda.
\frac{xb}{x}=\frac{-ax^{2}-c}{x}
Ikki tarafini x ga bo‘ling.
b=\frac{-ax^{2}-c}{x}
x ga bo'lish x ga ko'paytirishni bekor qiladi.
b=-ax-\frac{c}{x}
-ax^{2}-c ni x ga bo'lish.
Misollar
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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
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