ab^2+c=x eching

$$a b ^ { 2 } + c = x$$

a uchun yechish (complex solution)

$$\left\{\begin{matrix}a=-\frac{c-x}{b^{2}}\text{, }&b\neq 0\\a\in \mathrm{C}\text{, }&c=x\text{ and }b=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan c ni ayirish.

$$ab^{2}=x-c$$

Tenglama standart shaklda.

$$b^{2}a=x-c$$

Ikki tarafini b^{2} ga bo‘ling.

$$\frac{b^{2}a}{b^{2}}=\frac{x-c}{b^{2}}$$

b^{2} ga bo'lish b^{2} ga ko'paytirishni bekor qiladi.

$$a=\frac{x-c}{b^{2}}$$

a uchun yechish

$$\left\{\begin{matrix}a=-\frac{c-x}{b^{2}}\text{, }&b\neq 0\\a\in \mathrm{R}\text{, }&c=x\text{ and }b=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan c ni ayirish.

$$ab^{2}=x-c$$

Tenglama standart shaklda.

$$b^{2}a=x-c$$

Ikki tarafini b^{2} ga bo‘ling.

$$\frac{b^{2}a}{b^{2}}=\frac{x-c}{b^{2}}$$

b^{2} ga bo'lish b^{2} ga ko'paytirishni bekor qiladi.

$$a=\frac{x-c}{b^{2}}$$

b uchun yechish (complex solution)

$$\left\{\begin{matrix}b=-ia^{-\frac{1}{2}}\sqrt{c-x}\text{; }b=ia^{-\frac{1}{2}}\sqrt{c-x}\text{, }&a\neq 0\\b\in \mathrm{C}\text{, }&c=x\text{ and }a=0\end{matrix}\right,$$

b uchun yechish

$$\left\{\begin{matrix}b=\sqrt{\frac{x-c}{a}}\text{; }b=-\sqrt{\frac{x-c}{a}}\text{, }&\left(a>0\text{ or }c\geq x\right)\text{ and }\left(a<0\text{ or }c\leq x\right)\text{ and }a\neq 0\\b\in \mathrm{R}\text{, }&c=x\text{ and }a=0\end{matrix}\right,$$