a_{1}a+a_{1}a^3=10 eching

$$a _ { 1 } a + a _ { 1 } a ^ { 3 } = 10$$

a_1 uchun yechish

$$a_{1}=\frac{10}{a^{3}+a}$$

$$a\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

a_{1}'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(a+a^{3}\right)a_{1}=10$$

Tenglama standart shaklda.

$$\left(a^{3}+a\right)a_{1}=10$$

Ikki tarafini a+a^{3} ga bo‘ling.

$$\frac{\left(a^{3}+a\right)a_{1}}{a^{3}+a}=\frac{10}{a^{3}+a}$$

a+a^{3} ga bo'lish a+a^{3} ga ko'paytirishni bekor qiladi.

$$a_{1}=\frac{10}{a^{3}+a}$$

10 ni a+a^{3} ga bo'lish.

$$a_{1}=\frac{10}{a\left(a^{2}+1\right)}$$

a uchun yechish

$$a=\sqrt[3]{\frac{1}{9a_{1}|a_{1}|}}\left(\sqrt[3]{a_{1}\sqrt{3\left(a_{1}^{2}+675\right)}+45|a_{1}|}+\sqrt[3]{-a_{1}\sqrt{3\left(a_{1}^{2}+675\right)}+45|a_{1}|}\right)$$