aS=a1+(s-3)*3 eching

$$a S = a 1 + ( s - 3 ) \cdot 3$$

S uchun yechish

$$\left\{\begin{matrix}S=-\frac{9-a_{1}-3s}{a}\text{, }&a\neq 0\\S\in \mathrm{R}\text{, }&a_{1}=9-3s\text{ and }a=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

s-3 ga 3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$aS=a_{1}+3s-9$$

Tenglama standart shaklda.

$$aS=3s+a_{1}-9$$

Ikki tarafini a ga bo‘ling.

$$\frac{aS}{a}=\frac{3s+a_{1}-9}{a}$$

a ga bo'lish a ga ko'paytirishni bekor qiladi.

$$S=\frac{3s+a_{1}-9}{a}$$

a uchun yechish

$$\left\{\begin{matrix}a=-\frac{9-a_{1}-3s}{S}\text{, }&S\neq 0\\a\in \mathrm{R}\text{, }&a_{1}=9-3s\text{ and }S=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

s-3 ga 3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$aS=a_{1}+3s-9$$

Tenglama standart shaklda.

$$Sa=3s+a_{1}-9$$

Ikki tarafini S ga bo‘ling.

$$\frac{Sa}{S}=\frac{3s+a_{1}-9}{S}$$

S ga bo'lish S ga ko'paytirishni bekor qiladi.

$$a=\frac{3s+a_{1}-9}{S}$$