a(x+a)-x=a(a+1)+1 eching

$$a ( x + a ) - x = a ( a + 1 ) + 1$$

a uchun yechish

$$a=\frac{x+1}{x-1}$$

$$x\neq 1$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

a ga x+a ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$ax+a^{2}-x=a\left(a+1\right)+1$$

a ga a+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$ax+a^{2}-x=a^{2}+a+1$$

Ikkala tarafdan a^{2} ni ayirish.

$$ax+a^{2}-x-a^{2}=a+1$$

0 ni olish uchun a^{2} va -a^{2} ni birlashtirish.

$$ax-x=a+1$$

Ikkala tarafdan a ni ayirish.

$$ax-x-a=1$$

x ni ikki tarafga qo’shing.

$$ax-a=1+x$$

a'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(x-1\right)a=1+x$$

Tenglama standart shaklda.

$$\left(x-1\right)a=x+1$$

Ikki tarafini x-1 ga bo‘ling.

$$\frac{\left(x-1\right)a}{x-1}=\frac{x+1}{x-1}$$

x-1 ga bo'lish x-1 ga ko'paytirishni bekor qiladi.

$$a=\frac{x+1}{x-1}$$

x uchun yechish

$$x=\frac{a+1}{a-1}$$

$$a\neq 1$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

a ga x+a ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$ax+a^{2}-x=a\left(a+1\right)+1$$

a ga a+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$ax+a^{2}-x=a^{2}+a+1$$

Ikkala tarafdan a^{2} ni ayirish.

$$ax-x=a^{2}+a+1-a^{2}$$

0 ni olish uchun a^{2} va -a^{2} ni birlashtirish.

$$ax-x=a+1$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(a-1\right)x=a+1$$

Ikki tarafini -1+a ga bo‘ling.

$$\frac{\left(a-1\right)x}{a-1}=\frac{a+1}{a-1}$$

-1+a ga bo'lish -1+a ga ko'paytirishni bekor qiladi.

$$x=\frac{a+1}{a-1}$$