a(-63)+beta(3-9)=c-2 eching

$$a ( - 63 ) + \beta ( 3 - 9 ) = c - 2$$

a uchun yechish

$$a=-\frac{c}{63}-\frac{2\beta }{21}+\frac{2}{63}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-6 olish uchun 3 dan 9 ni ayirish.

$$a\left(-63\right)+\beta \left(-6\right)=c-2$$

Ikkala tarafdan \beta \left(-6\right) ni ayirish.

$$a\left(-63\right)=c-2-\beta \left(-6\right)$$

6 hosil qilish uchun -1 va -6 ni ko'paytirish.

$$a\left(-63\right)=c-2+6\beta$$

Tenglama standart shaklda.

$$-63a=c+6\beta -2$$

Ikki tarafini -63 ga bo‘ling.

$$\frac{-63a}{-63}=\frac{c+6\beta -2}{-63}$$

-63 ga bo'lish -63 ga ko'paytirishni bekor qiladi.

$$a=\frac{c+6\beta -2}{-63}$$

c-2+6\beta ni -63 ga bo'lish.

$$a=-\frac{c}{63}-\frac{2\beta }{21}+\frac{2}{63}$$

c uchun yechish

$$c=2-6\beta -63a$$