a*(a-2)-(a+2)^2-2a*(a-4)= eching

$$a \cdot ( a - 2 ) - ( a + 2 ) ^ { 2 } - 2 a \cdot ( a - 4 ) =$$

Baholash

$$2\left(-a^{2}+a-2\right)$$

Yechim qadamlari

a ga a-2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$a^{2}-2a-\left(a+2\right)^{2}-2a\left(a-4\right)$$

\left(p+q\right)^{2}=p^{2}+2pq+q^{2} binom teoremasini \left(a+2\right)^{2} kengaytirilishi uchun ishlating.

$$a^{2}-2a-\left(a^{2}+4a+4\right)-2a\left(a-4\right)$$

a^{2}+4a+4 teskarisini topish uchun har birining teskarisini toping.

$$a^{2}-2a-a^{2}-4a-4-2a\left(a-4\right)$$

0 ni olish uchun a^{2} va -a^{2} ni birlashtirish.

$$-2a-4a-4-2a\left(a-4\right)$$

-6a ni olish uchun -2a va -4a ni birlashtirish.

$$-6a-4-2a\left(a-4\right)$$

-2a ga a-4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-6a-4-2a^{2}+8a$$

2a ni olish uchun -6a va 8a ni birlashtirish.

$$2a-4-2a^{2}$$

Kengaytirish

$$-2a^{2}+2a-4$$

Yechim qadamlari

a ga a-2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$a^{2}-2a-\left(a+2\right)^{2}-2a\left(a-4\right)$$

\left(p+q\right)^{2}=p^{2}+2pq+q^{2} binom teoremasini \left(a+2\right)^{2} kengaytirilishi uchun ishlating.

$$a^{2}-2a-\left(a^{2}+4a+4\right)-2a\left(a-4\right)$$

a^{2}+4a+4 teskarisini topish uchun har birining teskarisini toping.

$$a^{2}-2a-a^{2}-4a-4-2a\left(a-4\right)$$

0 ni olish uchun a^{2} va -a^{2} ni birlashtirish.

$$-2a-4a-4-2a\left(a-4\right)$$

-6a ni olish uchun -2a va -4a ni birlashtirish.

$$-6a-4-2a\left(a-4\right)$$

-2a ga a-4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-6a-4-2a^{2}+8a$$

2a ni olish uchun -6a va 8a ni birlashtirish.

$$2a-4-2a^{2}$$