a^2x^2+(ab-a)x=2+2b eching

$$a ^ { 2 } x ^ { 2 } + ( a b - a ) x = 2 + 2 b$$

b uchun yechish (complex solution)

$$\left\{\begin{matrix}\\b=-\left(ax+1\right)\text{, }&\text{unconditionally}\\b\in \mathrm{C}\text{, }&a=\frac{2}{x}\text{ and }x\neq 0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

ab-a ga x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$a^{2}x^{2}+abx-ax=2+2b$$

Ikkala tarafdan 2b ni ayirish.

$$a^{2}x^{2}+abx-ax-2b=2$$

Ikkala tarafdan a^{2}x^{2} ni ayirish.

$$abx-ax-2b=2-a^{2}x^{2}$$

ax ni ikki tarafga qo’shing.

$$abx-2b=2-a^{2}x^{2}+ax$$

Shartlarni qayta saralash.

$$abx-2b=-a^{2}x^{2}+ax+2$$

b'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(ax-2\right)b=-a^{2}x^{2}+ax+2$$

Tenglama standart shaklda.

$$\left(ax-2\right)b=2+ax-a^{2}x^{2}$$

Ikki tarafini -2+ax ga bo‘ling.

$$\frac{\left(ax-2\right)b}{ax-2}=-\frac{\left(ax-2\right)\left(ax+1\right)}{ax-2}$$

-2+ax ga bo'lish -2+ax ga ko'paytirishni bekor qiladi.

$$b=-\frac{\left(ax-2\right)\left(ax+1\right)}{ax-2}$$

-\left(-2+ax\right)\left(1+ax\right) ni -2+ax ga bo'lish.

$$b=-\left(ax+1\right)$$

b uchun yechish

$$\left\{\begin{matrix}\\b=-\left(ax+1\right)\text{, }&\text{unconditionally}\\b\in \mathrm{R}\text{, }&a=\frac{2}{x}\text{ and }x\neq 0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

ab-a ga x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$a^{2}x^{2}+abx-ax=2+2b$$

Ikkala tarafdan 2b ni ayirish.

$$a^{2}x^{2}+abx-ax-2b=2$$

Ikkala tarafdan a^{2}x^{2} ni ayirish.

$$abx-ax-2b=2-a^{2}x^{2}$$

ax ni ikki tarafga qo’shing.

$$abx-2b=2-a^{2}x^{2}+ax$$

Shartlarni qayta saralash.

$$abx-2b=-a^{2}x^{2}+ax+2$$

b'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(ax-2\right)b=-a^{2}x^{2}+ax+2$$

Tenglama standart shaklda.

$$\left(ax-2\right)b=2+ax-a^{2}x^{2}$$

Ikki tarafini -2+ax ga bo‘ling.

$$\frac{\left(ax-2\right)b}{ax-2}=-\frac{\left(ax-2\right)\left(ax+1\right)}{ax-2}$$

-2+ax ga bo'lish -2+ax ga ko'paytirishni bekor qiladi.

$$b=-\frac{\left(ax-2\right)\left(ax+1\right)}{ax-2}$$

-\left(-2+ax\right)\left(1+ax\right) ni -2+ax ga bo'lish.

$$b=-\left(ax+1\right)$$

a uchun yechish (complex solution)

$$\left\{\begin{matrix}a=-\frac{b+1}{x}\text{; }a=\frac{2}{x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&b=-1\text{ and }x=0\end{matrix}\right,$$

a uchun yechish

$$\left\{\begin{matrix}a=-\frac{b+1}{x}\text{; }a=\frac{2}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&b=-1\text{ and }x=0\end{matrix}\right,$$