a^2(4a-3)^2-a(4a-3) eching

$$a ^ { 2 } ( 4 a - 3 ) ^ { 2 } - a ( 4 a - 3 )$$

Baholash

$$a\left(a-1\right)\left(4a-3\right)\left(4a+1\right)$$

Yechim qadamlari

\left(p-q\right)^{2}=p^{2}-2pq+q^{2} binom teoremasini \left(4a-3\right)^{2} kengaytirilishi uchun ishlating.

$$a^{2}\left(16a^{2}-24a+9\right)-a\left(4a-3\right)$$

a^{2} ga 16a^{2}-24a+9 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$16a^{4}-24a^{3}+9a^{2}-a\left(4a-3\right)$$

a ga 4a-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$16a^{4}-24a^{3}+9a^{2}-\left(4a^{2}-3a\right)$$

4a^{2}-3a teskarisini topish uchun har birining teskarisini toping.

$$16a^{4}-24a^{3}+9a^{2}-4a^{2}+3a$$

5a^{2} ni olish uchun 9a^{2} va -4a^{2} ni birlashtirish.

$$16a^{4}-24a^{3}+5a^{2}+3a$$

Kengaytirish

$$16a^{4}-24a^{3}+5a^{2}+3a$$

Yechim qadamlari

\left(p-q\right)^{2}=p^{2}-2pq+q^{2} binom teoremasini \left(4a-3\right)^{2} kengaytirilishi uchun ishlating.

$$a^{2}\left(16a^{2}-24a+9\right)-a\left(4a-3\right)$$

a^{2} ga 16a^{2}-24a+9 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$16a^{4}-24a^{3}+9a^{2}-a\left(4a-3\right)$$

a ga 4a-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$16a^{4}-24a^{3}+9a^{2}-\left(4a^{2}-3a\right)$$

4a^{2}-3a teskarisini topish uchun har birining teskarisini toping.

$$16a^{4}-24a^{3}+9a^{2}-4a^{2}+3a$$

5a^{2} ni olish uchun 9a^{2} va -4a^{2} ni birlashtirish.

$$16a^{4}-24a^{3}+5a^{2}+3a$$