a^2+7=13 eching

$$a ^ { 2 } + 7 = 13$$

a uchun yechish

$$a=\sqrt{6}\approx 2,449489743$$

$$a=-\sqrt{6}\approx -2,449489743$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 7 ni ayirish.

$$a^{2}=13-7$$

6 olish uchun 13 dan 7 ni ayirish.

$$a^{2}=6$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$a=\sqrt{6} a=-\sqrt{6}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 13 ni ayirish.

$$a^{2}+7-13=0$$

-6 olish uchun 7 dan 13 ni ayirish.

$$a^{2}-6=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -6 ni c bilan almashtiring.

$$a=\frac{0±\sqrt{0^{2}-4\left(-6\right)}}{2}$$

0 kvadratini chiqarish.

$$a=\frac{0±\sqrt{-4\left(-6\right)}}{2}$$

-4 ni -6 marotabaga ko'paytirish.

$$a=\frac{0±\sqrt{24}}{2}$$

24 ning kvadrat ildizini chiqarish.

$$a=\frac{0±2\sqrt{6}}{2}$$

a=\frac{0±2\sqrt{6}}{2} tenglamasini yeching, bunda ± musbat.

$$a=\sqrt{6}$$

a=\frac{0±2\sqrt{6}}{2} tenglamasini yeching, bunda ± manfiy.

$$a=-\sqrt{6}$$

Tenglama yechildi.

$$a=\sqrt{6} a=-\sqrt{6}$$