a uchun yechish
a=\frac{1+\sqrt{23}i}{2}\approx 0,5+2,397915762i
a=\frac{-\sqrt{23}i+1}{2}\approx 0,5-2,397915762i
Baham ko'rish
Klipbordga nusxa olish
a^{2}+2-a=-4
Ikkala tarafdan a ni ayirish.
a^{2}+2-a+4=0
4 ni ikki tarafga qo’shing.
a^{2}+6-a=0
6 olish uchun 2 va 4'ni qo'shing.
a^{2}-a+6=0
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
a=\frac{-\left(-1\right)±\sqrt{1-4\times 6}}{2}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, -1 ni b va 6 ni c bilan almashtiring.
a=\frac{-\left(-1\right)±\sqrt{1-24}}{2}
-4 ni 6 marotabaga ko'paytirish.
a=\frac{-\left(-1\right)±\sqrt{-23}}{2}
1 ni -24 ga qo'shish.
a=\frac{-\left(-1\right)±\sqrt{23}i}{2}
-23 ning kvadrat ildizini chiqarish.
a=\frac{1±\sqrt{23}i}{2}
-1 ning teskarisi 1 ga teng.
a=\frac{1+\sqrt{23}i}{2}
a=\frac{1±\sqrt{23}i}{2} tenglamasini yeching, bunda ± musbat. 1 ni i\sqrt{23} ga qo'shish.
a=\frac{-\sqrt{23}i+1}{2}
a=\frac{1±\sqrt{23}i}{2} tenglamasini yeching, bunda ± manfiy. 1 dan i\sqrt{23} ni ayirish.
a=\frac{1+\sqrt{23}i}{2} a=\frac{-\sqrt{23}i+1}{2}
Tenglama yechildi.
a^{2}+2-a=-4
Ikkala tarafdan a ni ayirish.
a^{2}-a=-4-2
Ikkala tarafdan 2 ni ayirish.
a^{2}-a=-6
-6 olish uchun -4 dan 2 ni ayirish.
a^{2}-a+\left(-\frac{1}{2}\right)^{2}=-6+\left(-\frac{1}{2}\right)^{2}
-1 ni bo‘lish, x shartining koeffitsienti, 2 ga -\frac{1}{2} olish uchun. Keyin, -\frac{1}{2} ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.
a^{2}-a+\frac{1}{4}=-6+\frac{1}{4}
Kasrning ham suratini, ham maxrajini kvadratga ko'paytirib -\frac{1}{2} kvadratini chiqarish.
a^{2}-a+\frac{1}{4}=-\frac{23}{4}
-6 ni \frac{1}{4} ga qo'shish.
\left(a-\frac{1}{2}\right)^{2}=-\frac{23}{4}
a^{2}-a+\frac{1}{4} omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.
\sqrt{\left(a-\frac{1}{2}\right)^{2}}=\sqrt{-\frac{23}{4}}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
a-\frac{1}{2}=\frac{\sqrt{23}i}{2} a-\frac{1}{2}=-\frac{\sqrt{23}i}{2}
Qisqartirish.
a=\frac{1+\sqrt{23}i}{2} a=\frac{-\sqrt{23}i+1}{2}
\frac{1}{2} ni tenglamaning ikkala tarafiga qo'shish.
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