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a=\frac{1}{2}\left(\left(\sqrt{7}\right)^{2}+2\sqrt{7}+1\right)
\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(\sqrt{7}+1\right)^{2} kengaytirilishi uchun ishlating.
a=\frac{1}{2}\left(7+2\sqrt{7}+1\right)
\sqrt{7} kvadrati – 7.
a=\frac{1}{2}\left(8+2\sqrt{7}\right)
8 olish uchun 7 va 1'ni qo'shing.
a=4+\sqrt{7}
\frac{1}{2} ga 8+2\sqrt{7} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.