X=-(-(-2/3))+(2/3);quadY=1+(2/5-4/3)-(frac{2}{5}-frac{4}{3}-1) eching

$$X = - ( - ( - \frac { 2 } { 3 } ) ) + ( \frac { 2 } { 3 } ) ; \quad Y = 1 + ( \frac { 2 } { 5 } - \frac { 4 } { 3 } ) - ( \frac { 2 } { 5 } - \frac { 4 } { 3 } - 1 )$$

X, Y uchun yechish

$$X=0$$

$$Y=2$$

Yechim qadamlari

Birinchi tenglamani yeching. -\frac{2}{3} ning teskarisi \frac{2}{3} ga teng.

$$X=-\frac{2}{3}+\frac{2}{3}$$

0 olish uchun -\frac{2}{3} va \frac{2}{3}'ni qo'shing.

$$X=0$$

Ikkinchi tenglamani yeching. \frac{7}{5} olish uchun 1 va \frac{2}{5}'ni qo'shing.

$$Y=\frac{7}{5}-\frac{4}{3}-\left(\frac{2}{5}-\frac{4}{3}-1\right)$$

\frac{1}{15} olish uchun \frac{7}{5} dan \frac{4}{3} ni ayirish.

$$Y=\frac{1}{15}-\left(\frac{2}{5}-\frac{4}{3}-1\right)$$

-\frac{14}{15} olish uchun \frac{2}{5} dan \frac{4}{3} ni ayirish.

$$Y=\frac{1}{15}-\left(-\frac{14}{15}-1\right)$$

-\frac{29}{15} olish uchun -\frac{14}{15} dan 1 ni ayirish.

$$Y=\frac{1}{15}-\left(-\frac{29}{15}\right)$$

-\frac{29}{15} ning teskarisi \frac{29}{15} ga teng.

$$Y=\frac{1}{15}+\frac{29}{15}$$

2 olish uchun \frac{1}{15} va \frac{29}{15}'ni qo'shing.

$$Y=2$$

Tizim hal qilindi.

$$X=0 Y=2$$