V=IRR eching

$$V = I R R$$

I uchun yechish (complex solution)

$$\left\{\begin{matrix}I=\frac{V}{R^{2}}\text{, }&R\neq 0\\I\in \mathrm{C}\text{, }&V=0\text{ and }R=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

R^{2} hosil qilish uchun R va R ni ko'paytirish.

$$V=IR^{2}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$IR^{2}=V$$

Tenglama standart shaklda.

$$R^{2}I=V$$

Ikki tarafini R^{2} ga bo‘ling.

$$\frac{R^{2}I}{R^{2}}=\frac{V}{R^{2}}$$

R^{2} ga bo'lish R^{2} ga ko'paytirishni bekor qiladi.

$$I=\frac{V}{R^{2}}$$

I uchun yechish

$$\left\{\begin{matrix}I=\frac{V}{R^{2}}\text{, }&R\neq 0\\I\in \mathrm{R}\text{, }&V=0\text{ and }R=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

R^{2} hosil qilish uchun R va R ni ko'paytirish.

$$V=IR^{2}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$IR^{2}=V$$

Tenglama standart shaklda.

$$R^{2}I=V$$

Ikki tarafini R^{2} ga bo‘ling.

$$\frac{R^{2}I}{R^{2}}=\frac{V}{R^{2}}$$

R^{2} ga bo'lish R^{2} ga ko'paytirishni bekor qiladi.

$$I=\frac{V}{R^{2}}$$

R uchun yechish (complex solution)

$$\left\{\begin{matrix}R=-I^{-\frac{1}{2}}\sqrt{V}\text{; }R=I^{-\frac{1}{2}}\sqrt{V}\text{, }&I\neq 0\\R\in \mathrm{C}\text{, }&V=0\text{ and }I=0\end{matrix}\right,$$

R uchun yechish

$$\left\{\begin{matrix}R=\sqrt{\frac{V}{I}}\text{; }R=-\sqrt{\frac{V}{I}}\text{, }&\left(V\geq 0\text{ and }I>0\right)\text{ or }\left(V\leq 0\text{ and }I<0\right)\\R\in \mathrm{R}\text{, }&V=0\text{ and }I=0\end{matrix}\right,$$