T=2pisqrt{l/98}quad[2] eching

$$T = 2 \pi \sqrt { \frac { l } { 98 } } \quad [ 2 ]$$

l uchun yechish

$$l=\frac{49\times \left(\frac{T}{\pi }\right)^{2}}{8}$$

$$T\geq 0$$

Ildizli tenglamalarni yechish qadamlari

4 hosil qilish uchun 2 va 2 ni ko'paytirish.

$$T=4\pi \sqrt{\frac{l}{98}}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$4\pi \sqrt{\frac{l}{98}}=T$$

Ikki tarafini 4\pi ga bo‘ling.

$$\frac{4\pi \sqrt{\frac{1}{98}l}}{4\pi }=\frac{T}{4\pi }$$

4\pi ga bo'lish 4\pi ga ko'paytirishni bekor qiladi.

$$\sqrt{\frac{1}{98}l}=\frac{T}{4\pi }$$

Tenglamaning ikkala taraf kvadratini chiqarish.

$$\frac{1}{98}l=\frac{T^{2}}{16\pi ^{2}}$$

Ikkala tarafini 98 ga ko‘paytiring.

$$\frac{\frac{1}{98}l}{\frac{1}{98}}=\frac{T^{2}}{\frac{1}{98}\times 16\pi ^{2}}$$

\frac{1}{98} ga bo'lish \frac{1}{98} ga ko'paytirishni bekor qiladi.

$$l=\frac{T^{2}}{\frac{1}{98}\times 16\pi ^{2}}$$

\frac{T^{2}}{16\pi ^{2}} ni \frac{1}{98} ga bo'lish \frac{T^{2}}{16\pi ^{2}} ga k'paytirish \frac{1}{98} ga qaytarish.

$$l=\frac{49T^{2}}{8\pi ^{2}}$$

T uchun yechish

$$T=\frac{2\pi \sqrt{2l}}{7}$$

$$l\geq 0$$